A model train with a mass of #8 kg# is moving along a track at #9 (cm)/s#. If the curvature of the track changes from a radius of #180 cm# to #81 cm#, by how much must the centripetal force applied by the tracks change?

Question

1059 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-29T05:23:55

The change in centripetal force is #=0.044N#

The centripetal force is

#F=(mv^2)/r#

mass, #m=(8)kg#

speed, #v=(0.09)ms^-1#

radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=8*0.09^2/1.8=0.036N#

#F_2=mv^2/r_2=8*0.09^2/0.81=0.08N#

#DeltaF=0.08-0.036=0.044N#