Question

How do you find the vertex for `y=x^2-x-2`?

Answer 1

Vertex is at `(1/2 , -2 1/4)`

Explanation:

`y= x^2 -x -2 or y= x^2 -x +(1/2)^2 -1/4 -2` or

`y= (x-1/2)^2 -9/4` , Comparing with vertex form of equation

`y= a (x-h)^2+k ; (h,k)` being vertex , we find here

`h=1/2 , k = -9/4` . So vertex is at `(1/2 , -2 1/4)`

graph{x^2-x-2 [-10, 10, -5, 5]} [Ans]