Question

Given `sintheta=6/11` and `sectheta>0`, how do you find `costheta, tantheta`?

Answer 1

`costheta=sqrt85/11` and `tantheta=6/sqrt85`

Explanation:

As `sintheta` and `sectheta` both are positive `theta` lies `Q1` and hence all trigonometricratios of `theta` are positive.

`costheta=sqrt(1-sin^2theta)=sqrt(1-(6/11)^2)`

`=sqrt(1-36/121)=sqrt(85/121)=sqrt85/11`

`tantheta=(6/11)/(sqrt85/11)=6/sqrt85`