Question

How do you factor `9t^3+66t^2-48t`?

Answer 1

See a solution process below:

Explanation:

First, we can factor a `3t` out of each term in the expression giving:

`(3t * 3t^2) + (3t * 22t) - (3t * 16t) =>`

`3t(3t^2 + 22t - 16t)`

Next, we can factor the quadratic as:

`3t(3t - 2)(t + 8)`