Question

How do you write the point slope form of the equation given (0,2) and (2,1)?

Answer 1

The equation is `y-2=-1/2(x-0)`

Explanation:

Point slope form of equation is `y-y_1=m(x-x_1)`, which represents equation of a line passing through point `(x_1,y_1)` and having a slope `m`.

As slope of line joining `(x_1,y_1)` and `(x_2,y_2)` is `(y_2-y_1)/(x_2-x_1)`, slope of line joining `(0,2)` and `(2,1)` is `(1-2)/(2-0)=-1/2`.

Hence, slope of desired line is `-1/2` and as it passed through `(0,2)`, point slope form of its equation is

`y-2=-1/2(x-0)`

or `2y-4=-x` or `x+2y-4=0`