How do you write an equation for the line in slope intercept form that is parallel to the given line and that passes through the given point y = x – 5; (–2, –16)?

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Answer 1 · 2017-08-12T12:27:44

The equaion of line in slope intercept form is # y =x-14 #

Parallel lines have equal slope. The slope of the line #y=x-5#

is #m= 1 # (Comparing with standard equation #y=mx+c# )

So the slope of the asked line is also #m=1 #

Let the equaion of the line is #y= mx+c or y =x+c#

The line passes through # (-2 ,-16) # , so the point will satisfy

the equation #:. -16 = -2 + c or c = -16 +2 =-14 #

Hence the equaion of line is # y =x-14 # [Ans]