Question

What is the %-ionization in a 0.20M solution of a weak acid, HA?

Answer 1

Unknown.......

Explanation:

You have the weak acid undergoing protonolysis in aqueous solution:

`HA(aq) + H_2O(l) rarrH_3O^(+) + A^(-)`

Now we calculate the extent of this equilibrium by use of the equation, `K_a=([H_3O^+][A^-])/([HA])`. But we ain't got a value of `K_a`; typical values of `K_a` for the weak acid `H_3C-CO_2H`, `K_a=1.73xx10^-5`; for `HF`, `K_a=6.76xx10^-4`; and for water, `K_a=10^-14`.

Over to you......