What is the simplest radical form of #2sqrt112#?

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Answer 1 · 2017-08-15T17:43:20

#8sqrt7#

Write the radicand as the product of its factors.
Usually prime factors is advisable, but in this case

#112 = 16xx7#

which is very useful because #16# is a square number.

#2sqrt112#

# = 2sqrt(color(red)(16) xx7)" "larr# find the roots if possible

#=2 xx color(red)(4)sqrt7#

#=8sqrt7#