Question

Question #6108a

Answer 1

`"mass" = 0.769` `"g"`

Explanation:

We're asked to find the mass of the diamond, given its density and volume it occupies.

To do this, we can look at the density equation:

`"density" = "mass"/"volume"`

And since we're solving for the mass, let's rearrange this to solve for mass:

`ul("mass" = ("density")("volume")`

We know:

• `"density" = 3.26` `"g/cm"^3`

• `"volume" = 0.326` `"cm"^3`

The mass is therefore

`"mass" = (3.26color(white)(l)"g/"cancel("cm"^3))(0.236cancel("cm"^3)) = color(red)(ulbar(|stackrel(" ")(" "0.769color(white)(l)"g"" ")|)`

rounded to `3` significant figures.