Question

How do you write the equation in point slope form given (-6,-3), m=-1?

Answer 1

`y+3=-1(x+6)`

Explanation:

`"the equation of a line in "color(blue)"point-slope form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))`
`"where m represents the slope and "(x_1,y_1)`
`"a point on the line"`

`"here "m=-1" and "(x_1,y_1)=(-6,-3)`

`rArry-(-3)=-1(x-(-6))`

`rArry+3=-1(x+6)larrcolor(red)" in point-slope form"`

Answer 2

`y+3 = -1(x+6)`

Explanation:

The point-slope formula for a straight line is `y-y_1 = m(x-x_1)`

For `(-6,-3), m =-1`

`y-(-3) = -1(x-(-6))`

`y+3 = -1(x+6)`

This can be simplified to give the other forms:

`y = -x-6-3`

`y= -x-9" "larr` this is slope-intercept form.

`x+y =-9" "larr` this is standard form