Question

How do you graph `y>=1/5x+10` on the coordinate plane?

Answer 1

See a solution process below:

Explanation:

First, solve for two points as an equation instead of a inequality to find the boundary line for the inequality.

For `x = 0`

`y = (1/5 * 0) + 10 = 0 + 10 = 10` or `(0, 10)`

For `x = -10`

`y = (1/5 * -10) + 10 = -2 + 10 = 8` or `(-10, 8)`

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

The boundary line will be solid because the inequality operator contains a "or equal to" clause.

graph{(y-1/5x-10)((x+10)^2+(y-8)^2-0.3)(x^2+(y-10)^2-0.3)=0 [-30, 30, -15, 15]}

To complete the chart of the inequality we shade the left side of the line:

graph{(y-1/5x-10)>=0 [-30, 30, -15, 15]}