How do you write the standard form of a line given Slope = -2; containing the point (3, -1)?

1 Answer
Aug 22, 2017

See a solution process below:

Explanation:

First, we can use the point-slope formula to write and equation for the line. The point-slope form of a linear equation is: #(y - color(blue)(y_1)) = color(red)(m)(x - color(blue)(x_1))#

Where #(color(blue)(x_1), color(blue)(y_1))# is a point on the line and #color(red)(m)# is the slope.

Substituting the slope from the problem and the values from the point in the problem gives:

#(y - color(blue)(-1)) = color(red)(-2)(x - color(blue)(3))#

#(y + color(blue)(1)) = color(red)(-2)(x - color(blue)(3))#

The standard form of a linear equation is: #color(red)(A)x + color(blue)(B)y = color(green)(C)#

Where, if at all possible, #color(red)(A)#, #color(blue)(B)#, and #color(green)(C)#are integers, and A is non-negative, and, A, B, and C have no common factors other than 1

We can now solve for this format as follows:

#y + color(blue)(1) = (color(red)(-2) xx x) - (color(red)(-2) xx color(blue)(3))#

#y + color(blue)(1) = -2x - (-6)#

#y + color(blue)(1) = -2x + 6#

#color(red)(2x) + y + color(blue)(1) - 1 = color(red)(2x) - 2x + 6 - 1#

#2x + y + 0 = 0 + 5#

#color(red)(2)x + color(blue)(1)y = color(green)(5)#