How do you find the zeros by rewriting the function #y=x^2+4x+3# in intercept form?
1 Answer
Aug 23, 2017
Explanation:
#"factorise the quadratic "x^2+4x+3#
#"the product of the factors of +3 which sum to + 4"#
#"are + 1 and + 3"#
#rArry=(x+1)(x+3)larrcolor(red)" in intercept form"#
#"to find the zeros equate y to zero"#
#rArr(x+1)(x+3)=0#
#"equate each factor to zero and solve for x"#
#x+1=0rArrx=-1#
#x+3=0rArrx=-3#
graph{x^2+4x+3 [-10, 10, -5, 5]}
