How do you graph #2x+y<=4# on the coordinate plane?
1 Answer
Aug 25, 2017
See a solution process below:
Explanation:
First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.
For
For
We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
The boundary line will be solid because the inequality operator contains a "or equal to" clause.
graph{(x^2+(y-4)^2-0.075)((x-2)^2+y^2-0.075)(2x+y-4)=0 [-15, 15, -7.5, 7.5]}
Now, we can shade the left side of the line for the "less than" clause in the inequality.
graph{(2x+y-4)<=0 [-15, 15, -7.5, 7.5]}