Question

What is the the vertex of `y = -x^2 - 12x - 4`?

Answer 1

Vertex is at `(-6,32)`

Explanation:

`y= -x^2-12x-4 or y = -(x^2+12x) -4`

`y = -(x^2+12x+36) +36 - 4`

`y = -(x+6)^2 +36 - 4 = -(x+6)^2 +32` . Comparing with

vertex form of equation `y = a(x-h)^2+k ; (h,k)` being vertex ,

we find here `h= -6 , k =32 :.` Vertex is at `(-6,32)` [Ans]