How do you solve the system of equations algebraically #-3x+10y=5, 2x+7y=24#?

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Answer 1 · 2017-08-26T10:50:57

Solution: #x=5 , y= 2#

# -3x+10y= 5 (1) , # 2x+7y = 24 (2) #

Multiplying equation (1) by #2# and equation (2) by #3#

we get , # -6x+20y= 10 (3) , # 6x+21y = 72 (4) #

Adding equation (3) and equation (4) we get,

#41 y=82 or y =82/41-2 # . Putting #y=2# in equation (1) we get,

# -3x + 10*2 =5 or -3x +20 =5 or 3x = 20-5 # or

# 3x =15 or x= 15/3= 5 #

Solution: #x=5 , y= 2# [Ans]