How do you graph the equation #y=-5/4x+1#?

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Answer 1 · 2017-08-29T18:05:50

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point:

For #x = 0#

#y = (-5/4 * 0) + 1#

#y = 0 + 1#

#y = 1# or #(0, 1)#

Second Point:

For #x = 4#

#y = (-5/4 * 4) + 1#

#y = -20/4 + 1#

#y = -5 + 1#

#y = -4# or #(4, -4)#

We can next graph the two points on the coordinate plane:

graph{(x^2+(y-1)^2-0.075)((x-4)^2+(y+4)^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y+5/4x-1)(x^2+(y-1)^2-0.075)((x-4)^2+(y+4)^2-0.075)=0 [-20, 20, -10, 10]}