Given density in #"g/L"#, how to calculate molar volume?
1 Answer
#barV = M/D#
#D# in#"g/L"#
#M# in#"g/mol"#
You can do that with a unit conversion. In principle, if you can convert from the density to the molar volume, you can convert from the molar volume to the density, so I will show the former case.
Given a density in
#=> "L"/"g"#
Now, since you want to cancel out
#"L"/cancel"g" xx cancel"g"/"mol" = "L"/"mol"# #color(blue)(sqrt"")#
What we've just done can be written in variables.
Given a density
#color(blue)(barV = M/D)#