How many atoms of mercury in a volume of #62.5*cm^3#?

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Answer 1 · 2017-09-03T12:20:57

Well, we know that #"density,"# #rho="Mass"/"Volume"#

And thus #"Mass"=rhoxx"volume"#

#=13.534*g*cm^-3xx62.5*cm^3=??*g#

And #"moles of mercury"="mass"/"molar mass"#

#=(13.534*g*cm^-3xx62.5*cm^3)/(200.59*g*mol^-1)=??*mol#

And we know that there are #6.022xx10^23# individual items of stuff in a mole....

And so #"atoms of mercury"#

#=(13.534*g*cm^-3xx62.5*cm^3)/(200.59*g*mol^-1)xx6.022xx10^23*mol^-1#

#=??#