A 4.60*L volume of gas at 845*mm*Hg pressure is expanded such that the new pressure is 368*mm*Hg. To what volume does it expand?
2 Answers
A measurement of
Explanation:
See this old question.......
To solve this question we would use.....
Explanation:
NOTE: Ideally, measurements of pressures greater than
We're asked to find the volume necessary for a gas system to exert a pressure of
To do this, we can use the pressure-volume relationship of gases illustrated by Boyle's law:
ulbar(|stackrel(" ")(" "P_2V_1 = P_2V_2" ")|)" " (constant temperature and quantity)
where
-
P_1 andP_2 are the initial and final pressures of the gas, respectively -
V_1 andV_2 are the inital and final volumes of the gas, respectively
We know:
-
P_1 = 845 "mm Hg" -
V_1 = 4.60 "L" -
P_2 = 368 "mm Hg" -
V_2 = ?
Let's rearrange the equation to solve for the final volume,
V_2 = (P_1V_1)/(P_2)
Plugging in known values:
color(red)(V_2) = ((845cancel("mm Hg"))(4.60color(white)(l)"L"))/(368cancel("mm Hg")) = color(red)(ulbar(|stackrel(" ")(" "10.6color(white)(l)"L"" ")|)