How do you graph the system of linear inequalities #4x>y# and #x<=12#?

2 Answers
Sep 5, 2017

Plot the two lines using calculated values.

Explanation:

The first one should have a dotted line along the y = 4x line, as the exact solution is not included. Shade the area below the line. The second one is just a solid line at x = 12 and shading on the left side of it.

The intersection of the two solutions is the common overlapping shaded area.
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Sep 5, 2017

graph{(4x-y)(12-x)^.5>0 [-156.6, 163.4, -91.5, 68.5]}

Explanation:

Draw the line #4x-y=0# passing for #(0;0)# and #(1;4)#.
Take a random easy point such as #P=(1;0)# that is to the "right" halfplane respect to the line; this point satisfy the inaquality #4x>y# because (#4>0#), so the "right" halfplane is the desired one.
The take only the zone with #x# less than 12.