How do you solve #3x - 5< - 2( x - 6) - 2#?

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Answer 1 · 2017-09-11T02:23:05

#x < 3#

#3x-5 < -2 (x-6) - 2" "# (expand brackets)

#3x-5 < -2x+ 12- 2" "# (#-2# from #12#)

#3x-5 < -2x + 10" "# (#+2x# on BS)

#5x-5 < 10" "# (#+5# on BS)

#5x < 15" "# (#-: 3# on BS)

#x < 3 #

-Fish