How do you factor # 162x^3 + 384#?
1 Answer
Sep 11, 2017
Explanation:
#"take out the "color(blue)"common factor"" of 6"#
#rArr6(27x^3+64)to(color(red)(1))#
#27x^3+64" is a "color(blue)"sum of cubes"#
#•color(white)(x)a^3+b^3=(a+b)(a^2-ab+b^2)#
#27x^3=(3x)^3rArra=3x#
#64=(4)^3rArrb=4#
#rArr27x^3+64=(3x+4)(9x^2-12x+16)#
#"returning to "(color(red)(1))#
#rArr162x^3+384=6(3x+4)(9x^2-12x+16)#
