How do you multiply #(8x + 9)(8x + 3) #? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Jumbotron · Aritra G. Sep 11, 2017 #64x^2 + 96x + 27# Explanation: We have, #y = (8x + 9) (8x + 3)# #implies y = 8x(8x + 9) +3 (8x + 9)# #implies y = 64x^2 + 72x + 24x + 27# Collect like terms #y = 64x^2 + (72x + 24x) + 27# #implies y = 64x^2 + 96x + 27# Therefore, #(8x + 9) (8x + 3) = 64x^2 + 96x + 27# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1231 views around the world You can reuse this answer Creative Commons License