How do you find the amplitude and period of #f(x) = 3 cos (2/3)x#?

1 Answer
Sep 16, 2017

#3,3pi#

Explanation:

#"the standard form of the cosine function is"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=acos(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude "=|a|," period "=(2pi)/b#

#"phase shift "=-c/b," vertical shift "=d#

#"here "a=3,b=2/3,c=d=0#

#rArr" amplitude "=|3|=3," period "=(2pi)/(2/3)=3pi#