Question

A charge of `9 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `5 J` to `2 J`, what is the voltage between points A and B?

Answer 1

`1/3"volt"`

Explanation:

`"Voltage between A and B"=-(U_B-U_A)/q`

`U_A=5J` and `U_B=2 J`
`V_(AB)=-(U_B-U_A)/q`
`V_(AB)=-(2-5)/9=1/3"Volt"`