Question

An object with a mass of `7 kg` is pushed along a linear path with a kinetic friction coefficient of `u_k(x)= 4+secx`. How much work would it take to move the object over #x in [(-5pi)/12, (pi)/6], where x is in meters?

Answer 1

The work is `=679.83J`

Explanation:

We need

`intsecxdx=ln(tanx+secx)+C`

The work done is

`W=F*d`

The frictional force is

`F_r=mu_k*N`

The normal force is `N=mg`

The mass is `m=7kg`

`F_r=mu_k*mg`

`=7*(4+secx)g`

The work done is

`W=7gint_(-5/12pi)^(1/6pi)(4+secx)dx`

`=7g*[4x+ln(tanx+secx)]_(-5/12pi)^(1/6pi)`

`=7g(4/6pi+ln(tan(pi/6)+sec(pi/6))-(-20/12pi+ln(tan(-5/12pi)+sec(-5/12pi))`

`=7g(9.91)`

`=679.83J`