Two rhombuses have sides with lengths of #15 #. If one rhombus has a corner with an angle of #pi/12 # and the other has a corner with an angle of #pi/2 #, what is the difference between the areas of the rhombuses?

1 Answer
Oct 3, 2017

Difference between areas #=108.22#

Explanation:

Rhombus 1
d1 and d2 are the diagonals.
Half of Corner angle #=(pi/12)/2=pi/24#
#sin(pi/24)=((d1)/2)/15#
#30sin(pi/24)=d1#
#d1=3.92#
Similarly, Other corner angle #=(2pi-(pi/6))/2=11pi/12#
#sin(11pi/24)=((d2/2)/15)#
#30sin(11pi/24)=d2#
#d2=29.74#
Area of rhombus #=(d1.d2)/2=3.92*29.74=color(red)(116.78)#

Rhombus 2
Since one corner angle is #pi/2#, all the corner angles are #pi/2# each, or it is square.
Area of square #=s^2=15^2=color(red)(225)#
Difference in area between Rhombus color(red)(1 & 2) is
#=225-116.78=color(blue)(108.22)#