How do you find period, amplitude, and midline of #f(t)=3cos(4t)+1#?

1 Answer
sankarankalyanam
Oct 13, 2017

#f(t)=3cos(4t+0)+1#
a Amplitude = 3
Period #=(2pi)/b=(2pi)/3#
Phase shift =(-c)/b=0#
Vertical shift d = 1

Explanation:

Standard form #y=a*cos(b(theta)+c)+d#
Where a is Amplitude and #(2pi)/b# is period,
c/b is phase shift & d is vertical shift**

#f(t)=3cos(4t+0)+1#
a Amplitude = 3
Period #=(2pi)/b=(2pi)/3#
Phase shift =(-c)/b=0#
Vertical shift d = 1

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