Question

How do you find the zeros by rewriting the function `h(x)=x^2-4x-77` in intercept form?

Answer 1

You may factorize.

Explanation:

After some trying you will find that:
`=(x-11)(x+7)` fits the bill, because:
`-77=(+7)xx(-11)` and `-4=-11+7`
This is called the product-sum method.

So the zeros are:
`x=+11andx=-7`