How do you find the amplitude, period and graph #y=3csc(1/2theta)#?

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Answer 1 · 2017-10-15T21:59:23

Amplitude none
Period #=(2pi)/(1/2)=4pi#
Phase shift #=0#
Vertical shift #=0#

graph{3csc(x/2) [-10, 10, -5, 5]}

#y=3 csc(theta/2)#

Standard form #a csc(bx-c) + d#

Since the graph of the function csc does not have a maximum or minimum value, there can be no value for the amplitude.

Period #= **(2pi)/b**#

Phase shift #= **c/b**#

Vertical shift #=**d**#

Amplitude none
Period #=(2pi)/(1/2)=4pi#
Phase shift #=0#
Vertical shift #=0#