Question

How do you write `(1-9i)(1-4i)(4-3i)` in standard form?

Answer 1

In standard form `(1-9i)(1-4i)(4-3i) = -179 +53 i`

Explanation:

`(1-9i)(1-4i)(4-3i) = ( 1 -13i - 36)(4-3i) [i^2=-1]`

`( -35 -13i )(4-3i) = -140 +53i -39 = -179 +53 i`

In standard form `(1-9i)(1-4i)(4-3i) = -179 +53 i` [Ans]