How do you graph #y=1/2sqrtx#, compare it to the parent graph and what is the domain and range?

1 Answer
Oct 22, 2017

The graph of #y# is the standard graph #f(x)=sqrtx# scaled by #1/2#
Domain: #[0, +oo)# Range: #[0, +oo)#

Explanation:

The graph of #y# is the standard graph #f(x)=sqrtx# scaled by #1/2#

The graphs of #y# (lower) and #sqrtx# (upper) are shown below.

graph{(1/2sqrt(x)-y)(sqrt(x)-y)=0 [-2.653, 9.833, -3.12, 3.125]}

#y# is defined #forall x in RR >=0#

Hence the domain of #y# is #[0, +oo)#

#y=0# at #x=0#

#y# has no finite upper bound.

Hence the range of #y# is also #[0, +oo)#