How do you find the period, phase and vertical shift of #y=csc(theta+pi)#?

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Answer 1 · 2017-10-31T10:11:14

Amplitude a =1

#Period = 2pi#

Phase shift # = pi#

Vertical shift #= 0#

#y=a csc(bx + c) + d# is the standard form of equation.
Amplitude a =1

#Period = (2pi) / b = 2pi#

Phase shift # = c / b = pi / 1 = pi#

Vertical shift #= d = 0#