How do you find the period, phase and vertical shift of $y=csc(theta+pi)$ ?

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Answer 1 · 2017-10-31T10:11:14

Amplitude a =1

$Period = 2pi$

Phase shift $= pi$

Vertical shift $= 0$

$y=a csc(bx + c) + d$ is the standard form of equation.
Amplitude a =1

$Period = (2pi) / b = 2pi$

Phase shift $= c / b = pi / 1 = pi$

Vertical shift $= d = 0$

How do you find the period, phase and vertical shift of y=csc(theta+pi)y=csc(theta+pi)?