How do you graph 3x<=13x1 on the coordinate plane?

1 Answer
Nov 1, 2017

See a solution process below:

Explanation:

Divide each side of the inequality by color(red)(3)3 to solve for xx while keeping the inequality balanced:

(3x)/color(red)(2) <= 1/color(red)(3)3x213

(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) <= 1/3

x >= 1/3

To graph this we will draw a vertical line at 1/3 on the horizontal axis.

The line will be a solid line because the inequality operator contains an "or equal to" clause.

We will shade to the left side of the line because the inequality operator also contains a "less than" clause:

graph{x <= 1/3 [-2, 2, -1, 1]}