Solve the equation #15cosA -8sinA=0#?

2 Answers
Somebody N. · Shwetank Mauria
Nov 1, 2017

#A ~~ 1.080839001# radians

Explanation:

#15cosA -8sinA=0#

#15cosA -8sinA=> (8sinA)/(15cosA)=1#

#sin(theta)/(cos(theta))=tan(theta)#

#:.#

#8/15tanA=1=> tanA = 15/8#

#A = arctan(tanA)= arctan(15/8)~~1.080839001#

Nghi N · Alan P.
Nov 4, 2017

#A = 61.93^@ + k180^@# or #61^@55.65'+k180^@# (for #k in ZZ#)

Explanation:

Divide both side by Cos A, condition #cos A != 0#, or #A != pi/2#, and #A != (3pi)/2#:
15 - 8tan A = 0
#tan A = 15/8#
Calculator and unit circle give:
#A = 61^@93 + k180^@#

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