How do you solve and graph #k+3/4>1/3#?

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Answer 1 · 2017-11-03T12:28:48

See a solution process below:

Subtract #color(red)(3/4)# from each side of the inequality to solve for #k# while keeping the inequality balanced:

#k + 3/4 - color(red)(3/4) > 1/3 - color(red)(3/4)#

#k + 0 > (4/4 xx 1/3) - (3/3 xx color(red)(3/4))#

#k > 4/12 - 9/12#

#k > -5/12#

To graph this we will draw a vertical line at #-5/12# on the horizontal axis.

The line will be a dashed line because the inequality operator does not contain an "or equal to" clause.

We will shade to the right side of the line because the inequality operator has a "greater than" clause:

graph{x>=-5/12 [-2, 2, -1, 1]}