How do you graph #2x – 4y > 8# and #y <3x + 1#?

1 Answer
Nov 5, 2017

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Explanation:

to get the intersections with the coordinate axes
for with the x axis y=0

#2x-4y=8#
when y=0
#2x=8#
#x=4#
then is the point (4,0)

now with the y axis, x=0
when x=0

#2x-4y=8#
#-4y=8#
#y=-2#
then is the point (0;-2)

then both points are located and the straight line is obtained
by being an inequality and having the greater sign, a line segment and shaded down is graphed

now #y<3x+1#

same for y=0

#0<3x+1#
#-1/3=x#

for x=0

#y<1#
#y=1#

it can also write as #3x+1>y# by being an inequality and having the greater sign, a line segment and shaded down is graphed