How do you graph #y=(1/5)^x#?

Question

4423 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-08T22:01:52

See below.

The curve intercepts the y axis when #x = 0#

#:.#

#y= (1/5)^0=1# coordinates #( 0 , 1 )#

as #x-> oo# #(1/5)^x-> 0#

So the x axis is a horizontal asymptote.

For negative #x# , #(1/5)^x# becomes:

#1/(1/5)^x#

as #x -> -oo# , #1/(1/5)^x->oo#

Graph:

enter image source here