How do you graph #y=(1/5)^x#?

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Answer 1 · 2017-11-08T22:01:52

See below.

The curve intercepts the y axis when #x = 0#

#:.#

#y= (1/5)^0=1# coordinates #( 0 , 1 )#

as #x-> oo# #(1/5)^x-> 0#

So the x axis is a horizontal asymptote.

For negative #x# , #(1/5)^x# becomes:

#1/(1/5)^x#

as #x -> -oo# , #1/(1/5)^x->oo#

Graph:

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