How do you solve #2x=sqrt[12x-5]# and find any extraneous solutions?
1 Answer
Nov 9, 2017
Start by squaring both sides...
Explanation:
...giving
...now you can subtract 12x and add 5 to both sides, giving:
...this is a quadratic equation with coefficients 4, -12, and 5.
Remember your forumula, if
...and for coefficients a = 4, b = -12, c = 5, your roots are:
2.5 and 0.5
GOOD LUCK