Question

How do you find the amplitude and period of `y=sec(8pit)`?

Answer 1

Amplitude `=1`, Period `=1/4`

Explanation:

Standard form of equation is
`y = a sec (bt - c) + d`

`a = 1, b = 8pi`

Amplitude `a = 1`

Period `= (2 pi) / |b|`

Period `= (cancel(2pi) / (cancel(8pi) 4)) = 1/4`