Question

How do you factor `125-8w^3`?

Answer 1

`(5-2w)(25+10w+4w^2)`

Explanation:

`"this is a "color(blue)"difference of cubes"`

`"and factorises in general as follows"`

`•color(white)(x)a^3-b^3=(a-b)(a^2+ab+b^2)`

`"here "(5)^3=125" and "(2w)^3=8w^3`

`rArra=5" and "b=2w`

`rArr125-8w^3`

`=(5-2w)(25+10w+4w^2)`