A model train with a mass of #6 kg# is moving along a track at #8 (cm)/s#. If the curvature of the track changes from a radius of #3 cm# to #15 cm#, by how much must the centripetal force applied by the tracks change?

Question

1223 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-18T07:50:55

The change in centripetal force is #=1.024N#

The centripetal force is

#F=(mv^2)/r#

The mass, #m=(6)kg#

The speed, #v=(0.08)ms^-1#

The radius, #=(r) m#

#r_1=0.03m#

#r_2=0.15m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=6*0.08^2/0.03=1.28N#

#F_2=mv^2/r_2=6*0.08^2/0.15=0.256N#

#DeltaF=F_1-F_2=1.28-0.256=1.024N#