A solid disk, spinning counter-clockwise, has a mass of #7 kg# and a radius of #3 m#. If a point on the edge of the disk is moving at #6 m/s# in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

Question

1176 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-19T07:58:27

The angular momentum is #=63kgm^2s^-1# and the angular velocity is #=2rads^-1#

The angular velocity is

#omega=(Deltatheta)/(Deltat)#

#v=r*((Deltatheta)/(Deltat))=r omega#

#omega=v/r#

where,

#v=6ms^(-1)#

#r=3m#

So,

The angular velocity is

#omega=(6)/(3)=2rads^-1#

The angular momentum is #L=Iomega#

The mass of the disc is #m=7kg#

For a solid disc, #I=(mr^2)/2#

So, #I=7xx(3)^2/2=31.5kgm^2#

The angular momentum is

#L=31.5xx2=63kgm^2s^-1#