Question

How do you find the period, amplitude and sketch `y=-sin((2pix)/3)`?

Answer 1

Amplitude = -1, Period = 3#

Explanation:

Standard form of equation is
`y = a sin (bx + c) + d`
Where amplitude = a, Period = `2pi/b`
Given equation is

`y = -sin((2pix)/3)`
graph{-sin(2pi x)/3 [-10, 10, -5, 5]}
Amplitude = a = -1
Period `= (2pi/b) = ((2pi)/((2pi)/3)) = 3`