Question

How do you find the amplitude, period and phase shift for `y=tantheta+1/2`?

Answer 1

Amplitude = 1, Period = `pi`, Phase shift = 2

Explanation:

Standard form of equation is
`y = a tan (bx -c) + d`
Where Amplitude = a, Period = `(pi/|b|)`, Phase shift = `c/b`

Given equation is `y = tan (theta + (1/2))`

graph{tan(x + (1/2)) [-10, 10, -5, 5]}

Amplitude = 1, Period =`(pi/1) = pi` & Phase shift = 1/(1/2) = 2#