Question

A projectile is shot from the ground at a velocity of `3 m/s` at an angle of `pi/4`. How long will it take for the projectile to land?

Answer 1

`"0.432 s"`

Explanation:

`v = "3 m/s" = sqrt((v_h)² + (v_v)²)`

`"Angle" = 45^@ => v_"horiz" = v_"vertik" = 3/sqrt(2)`

Since

`v = g t => t = v/g = 3/(sqrt(2) * g)`

`t =` time to fall, here we have the double of that: rise & fall

`=> T = 6/(sqrt(2) * g) = "0.432 s"`