Two opposite sides of a parallelogram each have a length of #6 #. If one corner of the parallelogram has an angle of #(7 pi)/8 # and the parallelogram's area is #18 #, how long are the other two sides?

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Answer 1 · 2017-12-02T10:25:31

Other two sides are #7.84# unit long.

We know the area of the parallelogram as #A_p=s_1s_2sin theta

Where #s_1=6,s_2=?,theta=(7pi)/8=157.5^0 # are the adjacent

sides and corner angle respectively.

#A_p=18 :. 18=6*s_2*sin157.5 or s_2= 18/(6*sin157.5)# or

#s_2 ~~7.84# unit. Other two sides are #7.84# unit long. [Ans]