Question

A `0.100 M` solution of chloroacetic acid (`ClCH_2COOH`) is `11.0%` ionized. Using this information, calculate `[ClCH_2COO^−]` and `[H^+]`?

Answer 1

`[ClCH_2COO^−]=[H^+]=0.011M=0.011molcolor(white)(l)dm^(-3)`

Explanation:

`[ClCH_2COOH]=0.100M`

As `11%` is ionised, the concentration of `ClCH_2COOH` is now `89%` of its original value. `0.1*0.89=0.089M`

Being a weak acid, we shall assume that `[ClCH_2COO^−]=[H^+]`

So, the concentrations for `ClCH_2COO^−` is the same as `H^+`.

The concentration which is ionised is `0.011M`, which is the concentration of the two ions.