Two opposite sides of a parallelogram each have a length of #6 #. If one corner of the parallelogram has an angle of #(7 pi)/8 # and the parallelogram's area is #5 #, how long are the other two sides?

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Answer 1 · 2017-12-09T11:50:31

The other two sides are 2.1775 long

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#/_A+ /_B= pi#
#/_B= (7pi)/8#
#:./_A= pi - (7pi)/8 = pi/8#

#sin A = h / AD#
Given #AD = 6, sin A = sin (pi/8) = 0.3827#

#h = AD * sin A = 6 * (1/2 )= 2.2962#

Area of parallelogram = AB * h = 5
#:. AB = 5 / 2.2962 = 2.1775#

The other two sides are #2.1775 # long